Average- Mean, Median & Mode (Chapter-1): 110 Important MCQs for Indian Competitive Exam Prep August 25, 2023 Quantitative AptitudeTest 1Test 2Test 3Test 4Test 5 Report a question What's wrong with this question?You cannot submit an empty report. Please add some details. 0% Average-Mean, Median & Mode Quiz-420 MCQs20 Marks30 Minutes 1 / 20The scores of a group of students in a math test are as follows: 23, 35, 28, 33, 5, 12, 40, 25, 20, 18, 1, 16. What is the first quartile of the data? 12 11 15 14 Solution:To find the first quartile (Q1), we need to arrange the data in ascending order. Since there are 12 data points, the median of the lower half (1st to 6th data points) will be the first quartile. 2 / 20The average of all the odd integers between 2 an 22 is 18 12 19 22 3 / 20The average of 8 numbers is 25. If the average of the first 4 numbers is 20 and the average of the last 4 numbers is 30, what is the value of the fifth number? 35 0 20 30 4 / 20The arithmetic mean (average) of the first ten whole numbers is 2 1.6 4.5 3.2 5 / 20B was born when A was 4 years 7 months old and C was born when B was 3 years 4 months old. When C was 5 years 2 months old, then their average age was : 8 years 9 months 8 years 11 months 7 years 3 months 8 years 7 months 6 / 20The average of six numbers is 32. If each of first three numbers is increased by 2 and each of the remaining three numbers is decreased by 4, then the new average is? 29 32 28 31 7 / 20The average of a set of numbers is 75. If each number is increased by 20 and then divided by 5, what will be the new average? 70 years 84 years 75 years 66 years Solution:If we add 20 to each number and then divide by 5, it's equivalent to adding 4 to each number. This won't change the average, as the adjustment is consistent for all numbers. Therefore, the new average remains 75. 8 / 20a The average age of group of 20 girls is 15 years and that of another group of 25 boys it is 24 years. The average age of the two groups mixed together is : 19.5 years 21 years 20 years 22 years 9 / 20Sachin Tendulkar has a certain average for 11 innings. In the 12th innings he scores 120 runs and thereby increases his average by 5 runs. His new average is : 60 70 65 68 Solution:Let the average of '11' innings is = x According to the statement, (11x+120)/12 = x+5 11x + 120 = 12x + 60 x = 60 Therefore, his new average = 60 + 5 = 65 10 / 20The average of 7 consecutive even numbers is 18. What is the largest of these numbers? 18 20 24 16 Solution:Since the numbers are consecutive even numbers, they have an interval of 2 between them. The middle number will be the average, which is 18. So, the largest number will be 18 + 2 * 3 = 24. 11 / 20The average of some natural numbers is 15. If 30 is added to the first number and 5 is subtracted from the last number the average becomes 17.5 then the number of natural numbers is: 15 25 20 10 12 / 20Out of 20 boys, 6 are each of 1 m 15 cm height, 8 are of 1 m 10 cm and rest of 1 m 12 cm. The average height of all of them is 114.0 cm 101.0 cm 122.2 cm 112.1 cm 13 / 20The heights (in inches) of a group of individuals are as follows: 63, 68, 71, 69, 72, 70, 66, 75, 73, 68. What is the 80th percentile height in this data set? 72.2 68 69 70.4 Solution:To find the 80th percentile, first arrange the data in ascending order: 63, 66, 68, 68, 69, 70, 71, 72, 73, 75. The position of the 80th percentile is calculated using the formula: Position = (Percentile / 100) * (N + 1) = (80 / 100) * (10 + 1) = 8.8. This means the 80th percentile falls between the 8th and 9th data points. Interpolating between these points: 80th Percentile = 8th value + 0.8 * (9th value - 8th value) = 72 + 0.8 * (73 - 72) = 72.2. So, the height corresponding to the 80th percentile is 72.2 inches. 14 / 20The average expenditure of a man for the first five months Rs. 1200 and for the next seven months is Rs. 1300. If he saves Rs. 2900 in that years, his monthly average income is 2200 1900 1200 1500 15 / 20The average of a dataset of 7 numbers is 50. If the average of the first 4 numbers is 45 and the average of the last 3 numbers is 55, what is the value of the seventh number? 6.5 5.5 5 6 16 / 20The mean of 9 observation is 16. One more observation is included and the new mean becomes 17. The 10th observation is 32 11 26 22 17 / 20Total weekly emoluments of the workers of a factory is Rs. 1534. Average weekly emolument of a worker is Rs. 118. The number of workers in the factory is: 19 14 12 13 18 / 20A student finds the average of 10, 2 digits numbers. If the digits of one of the numbers interchanged, the average increases by 3.6. The difference between the digits of the 2 digits number is 4 6 8 3 19 / 20The average of the first 100 positive integers is 51.5 50.5 100 50 Solution:Average of 'n' positive integer is = {n(n+1)}/(2-n) = (n+1)/2 20 / 20The average of 8 numbers is 20. The average of first two numbers is 15.5 and that of the next three is 21.33. If the sixth number be less than the seventh and eighth numbers by 4 and 7 respectively, them the eighth number is 22 30 25 18 Solution:Let the sixth number = x Then the seventh = x + 4 And the eighth = x + 7 According to the statement, {2-(31/2)}+{3-(64/3)}+x+x+4+x+7= 8-20 Solving it for x, x=18 Therefore, eighth number x + 7 = 18 + 7 = 25 Previous 1 2 3 4 5 6NextRelated Posts Time and Work Aptitude Questions (Chapter-10): Key 100 MCQs for Competitive Exams Practice Profit and Loss MCQs (Chapter-4): 100 Essential Questions for Competitive Exams in India Speed, Time & Distance Practice MCQs (Chapter-7): 100 Important Questions for Quantum Aptitude PreparationLeave a Reply Cancel Reply Save my name, email, and website in this browser for the next time I comment. I have read and accepted the Privacy Policy * Δ

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